Question

Daniel steps on the gas pedal of his car, and the engine increases its performance from zero to 2700 rpms (rotations per minute). What are the frequency and period?

[Hint: frequency is cycles per second]

Answer 1

Step-by-step explanation:

The frequency of the engine is given by :

`f=(rpm)/(60)`

We have, the engine increases its performance from zero to 2700 rpms.

Frequency,

`f=(2700)/(60)\ \text{cycles per second}\\\\f=45\ \text{cycles per second}`

The time period of the engine is given by :

T = f/f

So,

`T=(1)/(45)\ s\\\\T=0.023\ s`

Hence, the required frequency and the period is 45 cycles/second and 0.023 seconds respectively.