48.2k views
1 vote
How do you solve (3c)³ - (c - 4d)²; c = -2 AND d = 5

User Gatisl
by
7.4k points

1 Answer

3 votes
You just plug in the values.

[3*(-2)]^3 - (-2 - 4*5)^2

(-6)^3 - ( - 2 - 20)^2

-216 - (-22)^2

-216 - (484)

-216 - 484

-700
User Chris Pratt
by
7.2k points