Question

Question 2(Multiple Choice Worth 4 points)

(05.05)On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(1, 2). What is the length of Side RT of the polygon?

4 units
7 units
8 units
15 units

Answer 1

distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(-6,2)...x1 = -6 and y1 = 2
(1,2)....x2 = 1 and y2 = 2
now we sub
d = sqrt (1 - (-6^2) + (2 - 2)^2
d = sqrt (1 + 6) ^2 + 0
d = sqrt 7^2 + 0
d = sqrt 49
d = 7 units <===

Answer 2

The length of Side RT of the polygon is
`7\ units`

Explanation:

we know that

the formula to calculate the distance between two points is equal to

`d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}`

we have

`R(-6,2)\\T(1,2)`

substitute the values

`d=\sqrt{(2-2)^(2)+(1+6)^(2)}`

`d=\sqrt{(0)^(2)+(7)^(2)}`

`dRT=7\ units`