Question

How many molecules are in 41.8 g of sulfuric acid

Answer 1

× 10²³ molecules are in 41.8 g of sulfuric acid

Step-by-step explanation

The first step is to convert 41.8 g of sulfuric acid to moles by dividing the mass of sulfuric acid by its molar mass.

Molar mass of sulfuric acid, H₂SO₄ = 98.079 g/mol

`Mole=\frac{Mass}{Molar\text{ }mass}=\frac{41.8\text{ }g}{98.079\text{ }g\text{/}mol}=0.426187053\text{ }mol`

Finally, convert the moles of sulfuric acid to molecules using Avogadro's number.

Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.

Therefore, 0.426187053 moles of sulfuric acid is equal

`\frac{0.426187053\text{ }mol}{1\text{ }mol}*6.022×10²³\text{ }molecules=2.57*10^(23)\text{ }molecules`

Thus, 2.57 × 10²³ molecules are in 41.8 g of sulfuric acid.