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HELPP ANYONE???? The zero of the function in A(C)=9x^2-25/3x+5 is.... -5/3 5/3 5
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HELPP ANYONE????

The zero of the function in A(C)=9x^2-25/3x+5 is....

-5/3
5/3
5

User Luigi
by
7.7k points

1 Answer

6 votes
A(C)=9x^2-25/3x+5 = [3x+5)(3x-5)] / (3x -5) = 3x + 5

The zero of the function,
3x + 5 = 0
3x = -5
x = -5/3

answer
-5/3
User Kkyr
by
8.4k points
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