Question

Hello. Is it possible to get help with this question (Math 9.11 Solving Logarithmic Equations)

Answer 1

`\begin{gathered} 2lnx^(e+2)\text{ -lnx = 10} \\ 2(e+2)lnx\text{ - lnx = 10} \\ lnx(2(e+2)-1)=10 \\ lnx\text{ = 1.1853} \\ e^(lnx)\text{ = e}^(1.1853) \\ x\text{ = 3.27} \end{gathered}`

answer: x = 3.27