Given:
Point; (x, y) ==> (2, 5)
Slope, m = 2
To write a linear equation that goes through the point, apply the slop-intercept form:
y = mx + b
Where m is the slope and b is the y-intercept.
Take the following steps:
• Step 1:
Substitute 2 for m.
Input the points (2, 5) for the values of x and y repsectively
y = mx + b
5 = 2(2) + b
5 = 4 + b
• Step 2:
Solve for b.
Subtract 4 from both sides
5 - 4 = 4 - 4 + b
1 = b
Therefore, to write the linear equation, substitute 2 for m, and 1 for b in (y = mx + b)
y = mx + b
y = 2x + 1
Therefore, the equation for the line that goes through the point (2, 5) and has a slope of 2 is:
y = 2x + 1
ANSWER:
