Question

A clock moves past you at a speed of 0.9 c. How much time passes for you for each second that elapses on the moving clock?

0.436 s
1.15 s
2.29 s
infinity

Answer 1

2.29s

Step-by-step explanation:

Time dilation formula is

T = T₀ / √ 1-v²/c²

T₀ is time elapsed in moving reference , T time elapsed in stationary reference.

Here T₀ = 1 second

T = 1/√ 1-0.9² = 1/.4358 = 2.29 second

So 2.29 second will pass for each second on moving reference.

I got it right on the test :)