Question

find the zero(s) of f. round to the nearest tenth, if necessary. 1.y=(x-1)(x^2-7x+12) 2.y=(x-2)(x^2-4x+3)3.f(x)=x^2-4x+2. 4.f(x)=-x^2+2x+4answers i have for each one. (this is on a packet)H. 0.6, 3.4P. 1,2,3O. 1,3,4S.-1.3,3.2

Answer 1

1) The zeros of the function are 1, 3, 4

Step-by-step explanation:

1) y= (x-1)(x²-7x+12)

To find the zeros of the function above, we need to factorise the quadratic function and equate the factors to zero.

(x - 1) = 0 or (x²-7x+12) = 0

(x - 1) = 0

x - 1 = 0

x = 1

factorising (x²-7x+12):

(x²-7x+12) = 0

Factos of 12 whose sum gives -7 are -3 and - 4

x² - 3x - 4x + 12 = 0

x(x - 3) -4(x - 3) = 0

(x - 4)(x - 3) = 0

(x - 4) = 0 or (x - 3) = 0

x = 4 or x = 3

The zeros of the function are 1, 3, 4