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28 votes
Find the length of the shorter diagonal in a rhombus with an area of 30m ^ 2 if the lengths of the diagonals differ by 4 meters .

User Ytg
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1 Answer

16 votes
16 votes

rhombus

area= 30 m^2

Lengths =

lengths of the diagonals differ by 4 meters

A= (Diagonal 1* diagonal2) / 2

Diagonla 1 (D) = 4 + diagonal2 (d)

D= 4 + d (the largest diagonl)

d= (the sorthest diagonal)

A= 30 = (4 + d) *d/2

30 *2 = 4d + d^2

0 = d^2 + 4d - 60 (two numbers that added together give 4 and multiplied 60)

0 = (d + 10 ) (d - 6)

d= -10

d= 6 (this is the positive option)

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Answer

d= 6

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A= (Diagonal 1* diagonal2) / 2

A= (6+4)* 6/2 = 30

User Georgina
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