Question

Find the equation of the linear function which passes through the points (-1, 3) and (4, -2). give your answer in y = mx + b form.

Answer 1

Hello : let A(-1,3) B(4,-2)
the slope is : (YB - YA)/(XB -XA)
(-2-3)/(4+1) = -1
an equation is : y=ax+b a is a slope

y = -x +b

the line through point B(4,-2) : -2 = -1(4)+b
b = 2
the equation is : y =-x+2