1 Answer

Dymv · Answer 1 · 2018-05-03T01:16:01+0000

check the picture below. so the circle looks like so, and those points, are pretty much endpoints for the radius "r", thus

$\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -3}}\quad ,&{{ 3}})\quad % (c,d) &({{ 1}}\quad ,&{{ 6}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ r=√([1-(-3)]^2+[6-3]^2)\implies r=√((1+3)^2+(6-3)^2) \\\\\\ r=√(4^2+3^2)\implies r=√(25)\implies \boxed{r=5}\\\\ -------------------------------\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad r=5\implies \boxed{A=25\pi }$

The center of a circle is A (-3,3), and B (1,6) is on the circle. Find the area of-example-1

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Other Questions