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Aproximately 1 in 28 people of ashkenazi jewish descent are tay-sachs carrier. ... from this population, what is the probability neither is tay-sachs carrier?

1 Answer

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If we randomly pick two persons from the population, each one will have a probability of 1-1/28=27/28 of being a non-carrier.
Thus for neither to be non-carrier, the probability is the product of the individual probabilities since the picks are assumed independent (with a large enough population).

Probability = (27/28)*(27/28) = 729/784
or approximately 0.930
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