Question

An upward force of 27.5 N is applied via a string to lift up the a ball with a mass of 2.5 kg A . What is the magnitude and direction of the net force acting upon the ball?B. What is the magnitude and direction of acceleration of the ball?

Answer 1

Given:

The mass of the ball is m = 2.5 kg.

The upward force is F = 27.5 N

To find

(A)The direction and magnitude of the net force acting upon the ball.

(B)The direction and magnitude of the acceleration of the ball.

Step-by-step explanation:

(A) Two forces act on the ball, the upward force and the downward force due to gravity.

The net force will be

`\begin{gathered} F_(net)=F_{}-mg\text{ } \\ =27.5-2.5*9.8 \\ =\text{ 3 N} \end{gathered}`

Here, g = 9.8 m/s^2 is the acceleration due to gravity.

The direction of force is acting upwards.

(B) The magnitude of the acceleration is

`\begin{gathered} a\text{ = }(F_(net))/(m) \\ =(3)/(2.5) \\ =1.2m/s^2 \end{gathered}`

The direction of the acceleration is acting upwards.

Final Answer: (A)The magnitude of the net force is 3 N and the direction of force is upwards.

(B) The magnitude of the acceleration is 1.2 m/s^2 and the direction of the acceleration is acting upwards.