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Write an equation in slope-intercept form of the line that passes through the given point (-9,-8) and is parallel to the graph of the given equation y = -2x +4

User TPR
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1 Answer

18 votes
18 votes

Answer

y = -2x - 26

Step-by-step explanation

The slope and y-intercept form of the equation of a straight line is given as

y = mx + b

where

y = y-coordinate of a point on the line.

m = slope of the line.

x = x-coordinate of the point on the line whose y-coordinate is y.

b = y-intercept of the line.

The general form of the equation in point-slope form is

y - y₁ = m (x - x₁)

where

y = y-coordinate of a point on the line.

y₁ = This refers to the y-coordinate of a given point on the line

m = slope of the line.

x = x-coordinate of the point on the line whose y-coordinate is y.

x₁ = x-coordinate of the given point on the line

So, for this question, we will start with writing the equation in the point-slope form aswe are given the coordinates of a point on the line and a way to obtain the slope of the line first.

We will then simplify the result to obtain the equation of the line in slope-intercept form.

y - y₁ = m (x - x₁)

Point = (x₁, y₁) = (-9, -8)

For the slope, we will obtain it from the line parallel to our required line.

Parallel lines have the same slopes, and in y = -2x + 4,

Slope = -2

We can then write the equation for the line

y - y₁ = m (x - x₁)

y - (-8) = -2 [x - (-9)]

y + 8 = -2 (x + 9)

We will then simplify it to the required form

y + 8 = -2x - 18

y = -2x - 18 - 8

y = -2x - 26

Hope this Helps!!!

User Okarin
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