Question

The m<1=6x and m<3=120, find the value of x for p to be parallel to q

Answer 1

If p and q are parallel lines intersected by a transversal line, then the angles ∠1 and ∠3 are corresponding angles (the lines make an F-shape.). Corresponding angles are congruent so that:

`\begin{gathered} \angle1=\angle3 \\ 6x=120 \end{gathered}`

Divide both sides by 6 to determine the value of x

`\begin{gathered} (6x)/(6)=(120)/(6) \\ x=20 \end{gathered}`

For x=20 lines p and q can be considered to be parallel