64.0k views
1 vote
What are the solutions of 2x^2+3x=-8

User Dagang Wei
by
8.9k points

1 Answer

5 votes
The equation given above is written here below with all the terms transposed to only one side of the equation.
2x² + 3x + 8 = 0
The quadratic formula used for the determination of the roots is,
x = (-b +/- sqrt (b² - 4ac)) / 2a

In the quadratic equation above, we have the numerical coefficients.
a = 2
b = 3
c = 8

Substituting the known values,
x = (-3 +/- sqrt (3² - 4(2)(8))/ (2)(2)
x = -0.75 + 1.854i and x = -0.75 - 1.854i

By the calculated roots above, it is known that the roots are imaginary.
User Dda
by
9.1k points