Question

A closed-pipe resonator can produce sounds that have wavelengths that are four times the length of the pipe. Is this true or false?

Answer 1

The length of the pipe in terms of wavelength of the sound wave is,

`L=(1)/(4)\lambda`

Thus, the wavelength of the sound wave is,

`\lambda=4L`

where L is the length of the pipe.

`\lambda\text{ is the wavelength}`

Thus, the given statement is true.