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What are the solutions to the quadratic equation x^2-16=0

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Good evening.


This is a incomplete quadratic equation, because it does not have the term bx. Therefore, we can solve this faster with the following strategy:


\mathsf{x^2 - 16 = 0}

Add 16 to both sides:


\mathsf{x^2 - 16 + 16 = 0 + 16}\\ \\ \mathsf{x^2 = 16}

Take the square root:


\mathsf{\sqrt {x^2} = \pm√(16)}\\ \\ \mathsf{\boxed{\mathsf{x = \pm4} }}

Therefore:


\boxed{\boxed{\mathsf{S=\{-4, \ +4\}}}}
User Pavlos Panteliadis
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