Question

Find the equation of the line passing through the point (8, -4) and slope -4. y + 4x = 22y + 4x = 28y - 4x = 28y + x = 36

Answer 1

Step 1

Given; Find the equation of the line passing through the point (8, -4) and slope -4.

Step 2

The standard equation of a line in slope-intercept form is;

`\begin{gathered} y=mx+c \\ m=slope=-4 \\ c=y-intercept \end{gathered}`

Thus the equation will look like;

`\begin{gathered} y=-4x+c \\ y=-4 \\ x=8 \\ find\text{ c} \\ -4=-4(8)+c \\ -4=-32+c \end{gathered}`
`c=28`

Thus, the answer will be;

`\begin{gathered} y=-4x+28 \\ y+4x=28 \end{gathered}`