Question

What is the value for B, after the equation A=3/7(B-25) is rearranged?

Answer 1

To find B in terms of A (i hope this is what you want!) you can first multiply 3/7(B-25) by the reciprocal of 3/7, that being 7/3. You now have 7/3A=B-25, and through adding 25 on both sides, you have B=7/3A+25.

Hope this helps!

Answer 2

`B=(7A)/(3)+25`

Explanation:

We have been given an equation
`A=(3)/(7)(B-25)`. We are asked to find the value of B for our given equation.

Upon multiplying both sides of our equation by
`(7)/(3)`, we will get:

`(7)/(3)*A=(7)/(3)*(3)/(7)(B-25)`

`(7)/(3)*A=B-25`

`(7A)/(3)+25=B-25+25`

`(7A)/(3)+25=B`

`B=(7A)/(3)+25`

Therefore, the value of B is
`(7A)/(3)+25`.