Question

A boat of volume 8.71 x 10^6 cm^3 displaces a volume of 3.8 m³ of water. What is the magnitude of the buoyant force acting on the boat?

Answer 1

Given:

• Volume of boat = 8.71 x 10⁶ cm³

,

• Volume of water = 3.8 m³

Let's find the magnitude of the buoyant force acting on the boat.

To find the magnitude of the buoyant force acting on the boat, apply the formula:

Buoyant force = Volume dispersed x density of liquid x acceleration due to gravity

`F=v_d*\rho_(liquid)*g`

Where:

voulme dispersed = 3.8 m³

density of liquid = density of water = 1000 kg/m³

acceleration due to gravity = 9.8 m/s²

Thus, we have:

`\begin{gathered} F=3.8*1000*9.8 \\ \\ F=37240\text{ N} \end{gathered}`

Therefore, the magnitude of the buoyant force is 37240 N.

ANSWER:

37240 N