Question

Simplify 5 square root of 11 end root minus 12 square root of 11 end root minus 2 square root of 11.

negative 33 square root of 9
negative 11 square root of 9
negative 9 square root of 11
negative 9 square root of 33

Question 5(Multiple Choice Worth 1 points)



Simplify square root of 5 open parentheses 10 minus 4 square root of 2 close parentheses.

14
15 square root of 2
5 square root of 2 end root minus 4 square root of 10
None of the above

Question 6(Multiple Choice Worth 1 points)



Simplify square root of 3 times square root of 21.

square root of 24
square root of 63
3 square root of 7
None of the above

Answer 1

`-9√(11)`; None of the above;
`3√(7)`

Explanation:

For the first question:

`5√(11)-12√(11)-2√(11)`

Treating the radicals as a variable, we combine like terms:

`5√(11)-12√(11)-2√(11)\\\\=-7√(11)-2√(11)\\\\-9√(11)`

For the second question:

`5(10-4√(2))`

We use the distributive property:

`5(10-4√(2))\\\\5* 10-5*4√(2)\\\\50-20√(2)`

This is not one of the choices available.

For the third question:

`√(3)* √(21)`

We will first find the prime factorization of 21. 21 = 3*7:

`√(3)* √(3*7)`

These can all be written under one radical:

`√(3* 3* 7)`

For square roots, we want pairs of factors. We have a pair of 3s, so this comes out, giving us

`3√(7)`

Answer 2

Answer: Answer of First Question is -9√11, answer of second Question is 'None of the above' and answer of third question is 3√7

Explanation:

since, in first question, given expression is,

5√11-12√11-2√11

And, we can write, 5√11-12√11-2√11=-9√11

In other words, negative 9 square root of 11

Thus, option third is correct.

In second question, given expression is,

5(10-4√2),

And we can write, 5(10-4√2)=50-20√2

In other words, 50 minus 20 square root of 2.

Thus, Option fourth is correct.

In third question, given expression,

√3×√21,

And we can write, √3×√21=√3×√3×√7=3√7

Thus, third option is correct.