How many teams of 3 players can be chosen from 8 players?

asked Dec 24, 2018 79.4k views

5 votes

by Moez

7.8k points

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3 votes

$8C3=(8!)/(3!5!)=(6\cdot7\cdot8)/(2\cdot3)=56$

Urnenfeld answered Dec 26, 2018

8.5k points

6 votes

this is 8C3 = 8!
--------
5! 3!

A quick way to do this is 8*7*6
------- = 8*7 = 56
3*2*1

Tkymtk answered Dec 29, 2018

7.8k points

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