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7^-2 without exponent

User Nikso
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in any negative exponent problem all you do is flip the number(s) and or variable(s).
Ex: (7x)^-1 ----> 1 over 7x or 1/7x
Ex: (5/8x)^-1 ------> 8x over 5 or 8x/5
User Yashaka
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\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\ a^{-{ n}} \implies \cfrac{1}{a^( n)} \qquad \qquad \cfrac{1}{a^( n)}\implies a^{-{ n}} \qquad \qquad a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\ -------------------------------\\\\ 7^(-2)\implies \cfrac{1}{7^2}\implies \cfrac{1}{49}
User Nick Ruiz
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