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Y=-4x^2-8x-13 find the vertex of this parabola
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Y=-4x^2-8x-13 find the vertex of this parabola

User Darroosh
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1 Answer

3 votes
hello :
Y=-4x²-8x-13
= -4(x²+2x) -13
= -4 ((x² +2x+1)-1) -13
= -4 (x+1)² +4 -13
Y= -4 (x+1)² -9
the vertex is : (-1 , -9)


User Hunyadym
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