Question

If a rabbit accelerates from rest at 7.5 m/s2 for 3 seconds, how fast will it begoing? *

Answer 1

Given data:

* The initial velocity of the rabbit is u = 0 m/s.

* The acceleration of the rabbit is,

`a=7.5ms^(-2)`

* The time taken is t = 3 s.

Solution:

By the kinematics equation, the final velocity of the rabbit is,

`v-u=at`

Substituting the known values,

`\begin{gathered} v-0=7.5*3 \\ v=22.5\text{ m/s} \end{gathered}`

Thus, the velocity of the rabbit is 22.5 m/s.