Question

1Consider this right triangle.K1257°Enter the length of JL, to the nearest whole number.

Answer 1

To solve for the length of JL in the right triangle, we will apply

SOHCAHTOA

For this particular question, we will use CAH

`\cos \theta=(adjacent)/(hypotenuse)`
`\cos 57=(JL)/(12)`
`\text{Cross multiply}`
`\begin{gathered} 12*\cos 57=JL \\ 12*0.54464\text{ =JL} \\ 6.53568\text{ = JL} \\ 7\text{ (to the nearest whole number) = JL} \end{gathered}`