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Complete this statement 45ax^2+27 ax+18a=9a

User Leo Fang
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2 Answers

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Final answer:

This expression is a quadratic equation of the form ax² + bx + c = 0, where the constants are a = 45, b = 27, and c = 18. By substituting these values into the quadratic formula, we find that the equation has no real solutions.

Step-by-step explanation:

This expression is a quadratic equation of the form ax² + bx + c = 0, where the constants are a = 45, b = 27, and c = 18. To complete the statement, we need to find the values of x for which the equation is satisfied:

45ax² + 27ax + 18a = 9a

Simplifying the equation:

45ax² + 27ax + 18a - 9a = 0

45ax² + 27ax + 9a = 0

Dividing the equation by 9a:

5ax² + 3ax + 1 = 0

Now, we have a quadratic equation that we can solve using the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Substituting the values of a = 5, b = 3, and c = 1 into the formula:

x = (-3 ± √(3² - 4(5)(1))) / (2(5))

x = (-3 ± √(9 - 20)) / (10)

x = (-3 ± √(-11)) / (10)

Since the discriminant (b² - 4ac) is negative, the equation has no real solutions. Therefore, the statement cannot be completed with real values of x.

User CptBartender
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hello :
45ax²+27 ax+18a=9a
45ax² +27ax +9a =0
this statement is :
- if : a= 0 this expression = 0
- if : a
≠ 0 this expression = 45x²+27x+9

User Meyumer
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7.7k points