Question

A normal distribution has a mean of 60 and a standard deviation of 2. Determine the z-score for the data value of 22.

Answer 1

The formula for the z-score is given as:

`\begin{gathered} Z=(X-\mu)/(\sigma) \\ where, \\ \mu\text{ is the Mean} \\ \sigma\text{ is the Standard Deviation} \\ X\text{ is the value whose z-score we want to calculate} \end{gathered}`

- Thus, we can find the z-score as follows:

`\begin{gathered} X=22, \\ \\ Z=(22-60)/(2) \\ \\ Z=-19 \end{gathered}`