The hall voltage will be calculated using the formula:
E = Blv
where:
>Hall voltage: E = ?
>Magnetic field:
B = 0.200 Tesla or Wb/m^2
>Width of conductor or Diameter of Aorta:
l = 2.60 cm, converting to meter = .0260 m
>Velocity of charge flowing:
v = 60 cm/s, converting to meter = 0.6 m/s
Substituting the given :
E = (0.200 Wb/m^2) * (0.260 m) * (0.6 m/s)
E = (0.200 Wb/m^2) * (0.156 m^2/s)
E = 0.0312 Wb/s
Since 1 volt = 1 Wb/s then,
E = 0.0312 V or 31.2 mV