Question

The area of a rectangle is 52ft ^2 and the length of the rectangle is 5ft less than twice the width. Find the dimensions of the rectangle.

Answer 1

L * W = 52
L= (2w-5)
(2w-5) * w= 52
2w^2-5w= 52
2w^2-5w-52=0
(2w-13)(w+4)=0
2w=13
W= 13/2
W= 6.5 ft
L=2w-5
2(6.5)-5
13-5
L= 8 ft.
Hope this helps.