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A holiday punch recipe calls for 1500 mL of fruit punch, 375 ml of pineapple juice, and 1 liter of ginger ale. How many liters (L) of punch will this recipe yield if doubled?a. 12.5Lb. 3.05Lc. 2.875 Ld. 5.75 L

User Max Mikhaylov
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1 Answer

13 votes
13 votes

Given:

1500mL of fruit punch

375mL of pineapple juice

1 L of ginger ale

Find: total amount of liters (L) if punch is doubled

Solution:

We need to convert each content of recipe first into liters. Remember that for 1 liter = 1000mL.

Let's start converting the fruit punch first.


1500mL*(1L)/(1000mL)=(1500)/(1000)=1.5L

Now, let's convert the pineapple juice.


375mL*(1L)/(1000mL)=(375)/(1000)=0.375L

So, we have:

1.5L of fruit punch

0.375L of pineapple juice

1 L of ginger ale

Let's add them all and then, double it.


\begin{gathered} 1.5L+0.375L+1L=2.875L \\ \text{Double the recipe.} \\ 2*2.875L=5.75L \end{gathered}

Hence, there are 5.75L of punch of this recipe if doubled. (Option 4)

User A S
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