Question

When it is balanced, what is the weight on the right side of the hydraulic system?

Answer 1

`\begin{equation*} 40000N \end{equation*}`

Step-by-step explanation

We want to find the weight on the right side of the hydraulic system when it is balanced.

To do this, we apply Pascal's principle:

`(F_1)/(A_1)=(F_2)/(A_2)`

where F1 and A1 are the force and area of the left side of the system while F2 and A2 are the force and area of the right side of the system.

Hence, substituting the given values and solving for F2, the weight on the right side of the system is:

`\begin{gathered} (100)/(2)=(F_2)/(800) \\ F_2=(800*100)/(2) \\ F_2=40000N \end{gathered}`

That is the answer.