Question

Find the perimeter and the area of a rectangle with the sides 4 7/20 m and 6 2/3 m.

Answer 1

The perimeter of the rectangle is 22.04 meters, and the area is 29.0145 square meters. This was calculated using the side lengths 4.35 m and 6.67 m, derived from the given mixed numbers after conversion.

Step-by-step explanation:

To find the perimeter and the area of a rectangle with sides 4 7/20 meters (which converts to 4.35 m) and 6 2/3 meters (which converts to 6.67 m), the following steps can be taken:

1. Convert mixed numbers to improper fractions or decimals.
2. Use the perimeter formula P = 2(l + w) by plugging in the converted side lengths.
3. Calculate the area using the formula A = l * w with the side lengths.

For the perimeter:

P = 2(4.35 m + 6.67 m) = 2(11.02 m) = 22.04 m

For the area:

A = 4.35 m * 6.67 m = 29.0145 m2

So, the perimeter is 22.04 meters and the area is 29.0145 square meters.

Answer 2

9514 1404 393

Answer:

• perimeter: 22 1/30 m
• area: 29 m²

Step-by-step explanation:

The perimeter is given by the formula ...

P = 2(L+W)

P = 2(4 7/20 +6 2/3) = 2(10 +61/60) = 2(11 1/60)

P = 22 1/30 . . . . meters

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The area is given by the formula ...

A = LW

A = (4 7/20)(6 2/3) = (87/20)(20/3) = 87/3 = 29 . . . . square meters

The perimeter is 22 1/30 meters; the area is 29 square meters.