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What is the equation of the line in slope-intercept form that is perpendicular to the line y = x – 2 and passes through the point (–12, 10)? y = x – 6 y = x + 6 y = x + 26 y = x + 10
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What is the equation of the line in slope-intercept form that is perpendicular to the line y = x – 2 and passes through the point (–12, 10)? y = x – 6 y = x + 6 y = x + 26 y = x + 10

User Xavier Delaruelle
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6.2k points

2 Answers

2 votes
The slope of the given line y = x – 2 is 1. Therefore, the slope of a line perpendicular to y = x – 2 is -1/1, or just -1.

In point-slope form, the equation of the new line is

y-10 = -1(x-[-12]), or y-1 = -(x+12) or y-1 = -x - 12, or
y = -x - 11.
User Nobilik
by
6.9k points
4 votes

Answer:

y =-4/3 x – 6

Explanation:

User TetonSig
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7.6k points
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