Question

In a reaction, one mole of oxygen reacts with one mole of hydrogen. What mass of oxygen atoms is required to react completely with 30 g Of hydrogen atoms?

Answer 1

476.16 g of oxygen atoms

Step-by-step explanation

The reaction can be represented in the equation as shown below.

O₂ + H₂ → H₂O₂

According to the information given;

1 mole of O₂ reacts with 1 mole of H₂

1 mole of O₂ = 31.998 g/mol

1 mole of H₂ = 2.016 g/mol

This implies;

(1 mol x 31.998 g/mol) = 31.998 g of O₂ reacts with (1 mol x 2.016 g/mol) = 2.016 g of H₂

So, x g of O₂ will require 30 g of H₂

To get x, cross multiply and divide both sides by 2.016 g of H₂

`x=\frac{30\text{ }g\text{ }H₂}{2.016\text{ }g\text{ }H₂}*31.998\text{ }g\text{ }O₂=476.16\text{ }g\text{ }O₂`

Hence, 476.16 g of oxygen atoms is required to react completely with 30 g Of hydrogen atoms