Question

A tablet and a digital camcorder are both on sale for 30% off. The regular price of the tablet is $185. The regular price of the camcorder is $140. Part A Find the sale price of the tablet. Explain. Part B What is the sale price of the camcorder?

Answer 1

Part A

We need to find the sale price of the tablet, i.e., after a discount of 30% was applied.

When we apply a discount rate d to a price P, the sale price S is given by:

`S=(1-d)\cdot P`

In this problem, the original price of the tablet, in dollars, is:

`P=185`

And the discount rate is:

`d=30\%=(30)/(100)=0.3`

Then, the sale price is given by:

`S=(1-0.3)\cdot185=0.7\cdot185=129.5`

Therefore, the sale price of the tablet is $129.50.

Part B

Now, we can use the same formula to find the sale price of the camcorder, using:

`\begin{gathered} P=140 \\ d=0.3 \end{gathered}`

We obtain:

`S=(1-0.3)\cdot140=0.7\cdot140=98`

Therefore, the sale price of the camcorder is $98.