How many real solutions does the equation \displaystyle 4x^2-8x+10=-x^2-54x 2 −8x+10=−x 2 −5 have?

Joe Hildebrand asked Jul 9, 2023

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Joe Hildebrand asked Jul 9, 2023

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23 votes

$\begin{gathered} 4x^2-8x+10=-x^2-5 \\ \text{Put like terms together, we have:} \\ 4x^2+x^2-8x+10+5=0 \\ 5x^2-8x+15=0 \end{gathered}$

We cannot factorize, hence, we will use the quadratic formula:

Kdecom answered Jul 15, 2023

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