Question

Two endpoints of the diagonal of a parallelogram are k(0,3) and l(4,1). what is the length of the diagonal

Answer 1

distance = sqrt (x2 - x1)^2 + (y2 - y1)^2
(0,3).....x1 = 0 and y1 = 3
(4,1)....x2 = 4 and y2 = 1
now we sub and solve
d = sqrt (4 - 0)^2 + 1 - 3)^2
d = sqrt (4^2) + (-2^2)
d = sqrt (16 + 4)
d = sqrt 20
d = 4.472 <==