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If x varies jointly as y and z, and x = 8 when y = 4 and z = 9, find z when x = 16 and y = 6. 3

User Green Ho
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2 Answers

3 votes

Answer:

z = 12.7

Explanation:

x = kyz

Where K is the constant of proportionality. We will be finding this

When x = 8 y =4 z = 9

K = 8/4 x 9 = 8/36

K = 0.2

To find z, when x = 16 and y = 6.3

Z = x/ky = 16/ 0.2x6.3 = 12.7

User Yan Koshelev
by
7.9k points
4 votes

Answer:

Joint variation says that:

if
x \propto y and
x \propto z

then the equation is in the form of:


x = kyz, where, k is the constant of variation.

As per the statement:

If x varies jointly as y and z

then by definition we have;


x=k(yz) ......[1]

Solve for k;

when x = 8 , y=4 and z=9

then

Substitute these in [1] we have;


8=k(4 \cdot 9)


8 = 36k

Divide both sides by 36 we have;


(8)/(3)=k

Simplify:


k = (2)/(9)


x = (2)/(9)yz

to find z when x = 16 and y = 6

Substitute these value we have;


16 = (2)/(9) \cdot 6 \cdot z


16 = (12)/(9)z

Multiply both sides by 9 we have;


144 = 12z

Divide both sides by 12 we have;

12 = z

or

z = 12

Therefore, the value of z is, 12

User Pepijn Olivier
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8.9k points