Question

How would you simplify -2+3i/-3-2i (im doing conjugates in math right now)

Answer 1

To simplify -2+3i/-3-2i, multiply both the numerator and denominator by the conjugate of the denominator (-3+2i).

Step-by-step explanation:

To simplify -2+3i/-3-2i, we can multiply both the numerator and denominator by the conjugate of the denominator, which is -3+2i. This will help us eliminate the imaginary terms in the denominator.

Multiplying the numerator and denominator, we get:

(-2+3i)(-3+2i) / (-3-2i)(-3+2i)

Expanding and simplifying:

(6i+4i^2-9+6i) / (9+4)

Combining like terms:

(-9+12i+4i^2) / 13

Since i^2 is equal to -1, the expression becomes:

(-9+12i-4) / 13

Combining like terms:

(-13+12i) / 13

Therefore, the simplified form of -2+3i/-3-2i is (-13+12i) / 13.

Answer 2

`\cfrac{-2+3i}{-3-2i}= \\ \\ \\ \cfrac{(-2+3i)(-3+2i)}{(-3-2i)(-3+2i)}= \\ \\ \\ \cfrac{6-4i-9i+6i^2}{9-4i^2}= \\ \\ \\ \cfrac{6-13i-6}{9+4}= \\ \\ \\ \cfrac{-13i}{13}=-1i`

hope this helps