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Evaluate the function g(x) = –2x2 + 3x – 5 for the input values –2, 0, and 3.

User Jsmith
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2 Answers

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Final answer:

To evaluate the quadratic function g(x) = −2x² + 3x − 5, we substitute the input values −2, 0, and 3 into the function and calculate the outputs, which are −19, −5, and −14, respectively.

Step-by-step explanation:

The question involves evaluating a quadratic function g(x) = −2x² + 3x − 5 for specific values of x. To find the output values of the function, we plug in the given input values and perform the required calculations.

  • For x = −2: g(−2) = −2(−2x-2) + 3(−2) − 5 = −8 − 6 − 5 = −19
  • For x = 0: g(0) = −2(0)2 + 3(0) − 5 = −5
  • For x = 3: g(3) = −2(3)2 + 3(3) − 5 = −18 + 9 − 5 = −14

The evaluated values for g(x) at the given points are −19, −5, and −14, respectively.

User Ihuston
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g(x) = –2x2 + 3x – 5

input = –2, g(-2) = –2(-2)^2 + 3(-2) – 5 = -8 - 6 - 5 = -19

input = 0, g(0) = –2(0)^2 + 3(0) – 5 = -5

input = 3, g(3) = –2(3)^2 + 3(3) – 5 = -18 + 9 - 5 = -14
User Jun Yin
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