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What is the value of x in the equation 3x- 4y =65, when y= 4?

User Kyle Davis
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3x-4y=65

3x=65+4y

x=(65+4y)/3, when y=4

x=(65+4*4)/3

x=(65+16)/3

x=81/3

x=27
User Rob Conklin
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Answer: The required value of x when y = 4 is 27.

Step-by-step explanation: We are given to find the value of x in the following equation when y = 4 :


3x-4y=65~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To find the value of x, first we should write equation (i) as y as the dependent variable.

From equation (i), we have


3x-4y=65\\\\\Rightarrow 3x=65+4y\\\\\Rightarrow x=(65+4y)/(3)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Now, substituting y = 4 in equation (ii), we get


x\\\\\\=(65+4y)/(3)\\\\\\=(65+4*4)/(3)\\\\\\=(65+16)/(3)\\\\\\=(81)/(3)\\\\=27.

Thus, the required value of x when y = 4 is 27.

User Glennreyes
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