Question

Find the coordinates of point Q that lies along the directed line segment from R(-2, 4) to S(18, -6) and partitions the segment in the ratio of 3:7.

Please help!!

Answer 1

check the picture below

thus then


`\bf \qquad \textit{internal division of a line segment}\\\\ R(-2,4)\qquad S(18,-6)\qquad ratio1=3\qquad ratio2=7\qquad 3:7\\ \quad \\ \quad \\ \cfrac{RQ}{QS}=\cfrac{ratio1}{ratio2}\implies \cfrac{R}{S}=\cfrac{3}{7} \implies 7R=3S \\\\\\ 7(-2,4)=3(18,-6)`


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