Question

You and two friends visit a pizza shop. There are 14 toppings. 7 toppings are meat and the rest are vegetable. Each of you order a different topping (no repeats) at random. What is the probability that your group orders only meat toppings?

Answer 1

So there are three people. There are 7 meats and 7 vegetable choices.

So the probability of picking 3 meats in a row is:

P(MMM)=(7/14)(6/13)(5/12)

P(MMM)=210/2184

P(MMM)=5/52 (≈9.62%)

Answer 2

Answer:
`(5)/(52)`

Explanation:

Given: Total toppings = 14

Meat toppings =7

By using permutations,

If each of three friends order a different meat toppings , then total ways of order toppings
`14*13*12`

If the group is ordering only meat topping then the number of ways to order only meat topping
`7*6*5`

Then, the probability that the group orders only meat toppings
`(14*13*12)/(7*6*5)=(5)/(52)`