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What is the empirical formula of a compound that is 56.95% cu, 14.37% s, and 28.68% o?
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What is the empirical formula of a compound that is 56.95% cu, 14.37% s, and 28.68% o?

User Shaswat Rungta
by
8.4k points

1 Answer

6 votes
Assume 100g

Cu = 56.95/63.5 = 0,89685
S = 14.37/32 = 0.44906
O = 28.68/16 = 1.7925

Divide by the smallest

2:1:4

Therefore the formula is cu2so4
User Keaplogik
by
7.9k points
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