Question

In a line segment if the midpoint is at (-4,8) and one of the endpoints is at (12,6) where is the other endpoint

Answer 1

`\begin{gathered} \text{mid point = (}(x_1+x_2)/(2),(y_1+y_2)/(2)\text{)} \\ x_1=12 \\ y_1=6 \\ (-4,8)\text{ = (}\frac{12_{}+x_2}{2},\frac{6_{}+y_2}{2}\text{)} \\ -4=(12+x_2)/(2) \\ -8=12+x_2 \\ -8-12=x_2 \\ x_2=-20 \\ \\ 8=(6+y_2)/(2) \\ 16=6+y_2 \\ 16-6=y_2 \\ y_2=10 \\ (x_(2,)y_2)=(-20,10) \end{gathered}`