Question

According to the general equation for conditional probability, of P(A^B') = 1/6 and P(B')= 7/12 , what is P(A l B')?

Answer 1

Definition of conditional probability:
P(A|B)=P(A^B)/P(B)

In this case, B is replaced by B', so
P(A|B')=P(A^B')/P(B')=(1/6)/(7/12)=2/7

Answer 2

Answer:
`P(A|B')=(2)/(7)`

Explanation:

• The general equation for conditional probability :

`P(M|N)=(P(M\cap N))/(P(N))`

Given : P(A∩B') = 1/6 and P(B')= 7/12

According to the general equation for conditional probability, we have

`P(A|B')=(P(A\cap B'))/(P(B'))\\\\\Rightarrow\ P(A|B')=((1)/(6))/((7)/(12))\\\\\Rightarrow\ P(A|B')=(1)/(6)*(12)/(7)\\\\\Rightarrow\ P(A|B')=(2)/(7)`

Hence,
`P(A|B')=(2)/(7)`