Answer:
Dividend=Divisor×Quotient+Remainder
So, Applying it:−
Let q(x),k(x) be quotient when f(x) is divided by x−1 and x−2 respectively
⇒f(x)=(x−1)q(x)+5
∴f(1)=5 ..... (1)
Also,f(x)=(x−2)k(x)+7
∴f(2)=7 ..... (2)
Now, let ax+b be the remainder when f(x) is divided by (x−1)(x−2) and g(x) be the quotient.
f(x)=(x−1)(x−2)g(x)+(ax+b)
Using (1) and (2)
5=a+b ...... (3)
7=2a+b ...... (4)
Solving (3) and (4), we get
a=2 and b=3
∴2x+3 is the remainder when f(x) is divided by (x−1)(x−2).